Math
posted by Simon .
A box measures 60cm*52cm*40cm.find the area of the cardboards required to make 280 such boxes.
Respond to this Question
Similar Questions

math
Sue wants to frame a picture with a matte of uniform width all around the print. Sue wants the area of the matte to equal the area of the picture. If the print measures 60cm by 40cm how wide should the matte be? 
Algebra 2
Linear Programming Your club is making boxes and plant hangers to sell as a fundraiser. Your profit is $10 for a box and $8 for a hanger. How many boxes and hangers should you make in order to maximize your profit under the following … 
Math
A piece of cardboard has a length of 60cm and a width of 40cm. In order to make the cardboard into an open box, a box with no lid), a piece of length x must be cut out of each corner. Write an equation to represent each dimension of … 
Geometry
A company produces cardboard boxes with the top, bottom and sides measuring 5 feet. It costs the company 4 cents a square foot to make each box. The square footage is determined by finding the area of all six sides of the box. Find … 
math
I need help please help me. There's a chart that has to have 16boxes. It has to be 4 by 4. Lable boxes that are vertical top to bottom 1,2,3,4 and boxes that are horizontal left to right A,B,C,D. Box 1A has to be 28,Box 1C has to be … 
Math
This is math qustn plz help me to solve it bcz tmrw my test soreply soon as soon A box measures 60cm*52cm*40cm.find the area of the cardboards required to make 280 such boxes. 
Math
This is math qustn plz help me to solve it bcz tmrw my test soreply soon as soon A box measures 60cm*52cm*40cm.find the area of the cardboards required to make 280 such boxes. 
math
Flora’s class collected 236 books. They are placing the books in boxes. If each box holds 8 books, how many boxes can they fill? 
math
A trapezium ABCD is such that AB//CD and the perpendicular from A to CD is 40cm.if AB=20cm,DA=50cm and CD=60cm.calculate the (i)area of the trapezium (ii)<BCD.pls help me with (ii) solution so far.(i)area=1/2(20 60)40 =1600cm^2 
Math
1. Make a sketch of 5 rectangular open boxes such that a. the height of the boxes are the same, b. The boxes can hold 249cm^3, 504 cm^3,810 cm^3 and 468 cm^3 respectively. 2. Solve each quadratic equation by completing the square to …