a person stands on a bathroom scale that rest on the floor of an elevvator. when the elivetor is stationary the scale registers 50kg. when the lift acclelerates up ward the scle registers 60kg .taking g=10m/s^2, the best estimate acceleration of the lift is ;

m = 50 kg

weight = 50 * g
F = m a
f up from scale - m g = m a

60 * g - 50 * g = 50 * a
10 g = 50 a

a = 0.2 g
if g = 9.91 m/s^2
then a = 1.96 m/s^2

To determine the acceleration of the elevator, we can use Newton's second law of motion which states that force is equal to the mass of an object multiplied by its acceleration (F = ma).

In this case, the force acting on the person is their weight. When the elevator is stationary, the scale registers a weight of 50 kg. Therefore, the force acting on the person is:

Force = Mass * Acceleration due to gravity
50 kg * 10 m/s^2 = 500 N

When the elevator accelerates upward, the scale registers a weight of 60 kg. This means that the force acting on the person has increased to:

60 kg * 10 m/s^2 = 600 N

The difference in force between the stationary and upward accelerating elevator is 600 N - 500 N = 100 N.

Since force is equal to mass multiplied by acceleration, we can set up the following equation:

100 N = Mass * Acceleration

We know the mass is 50 kg, so we can rearrange the equation to solve for the acceleration:

Acceleration = 100 N / 50 kg = 2 m/s^2

Therefore, the best estimate for the acceleration of the elevator is 2 m/s^2.