Two resistors 3 Ù and 6 Ù are connected in parallel across a 6 V battery. What is the current flow through the 3 Ù resistor?
If in parallel, other resistor is irrelevant
i = 6 v / 3 ohms = 2 amps
Thank you!
To find the current flow through the 3 Ù resistor, we need to apply Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by its resistance (R).
In this case, we are given that the two resistors (3 Ù and 6 Ù) are connected in parallel across a 6 V battery. When resistors are connected in parallel, the voltage across each resistor is the same, which is equal to the battery voltage.
So, the voltage across the 3 Ù resistor is also 6 V. Now we can use Ohm's Law to find the current flow through the resistor:
I = V / R
Plugging in the values, we have:
I = 6 V / 3 Ù
Simplifying this expression, we get:
I = 2 A
Therefore, the current flow through the 3 Ù resistor is 2 Amperes (A).