Can someone pls help me!!
You decide to establish a new temperature scale on which the melting point of ammonia (-77.75 C ) is 0 A, and the boiling point of ammonia (-33.35 C ) is 200 A.
What would be the boiling point of water in A ?
What would be the temperature of absolute zero in A ?
Where did you get 44.4 from
I used slope to find the answer to the first part which was correct... the second part is what I need help with
The difference between -77.75 and -33.35 is 44.4; the difference between the two in A is 200 (i.e., 0 to 200).
This means that 200 A= 44.4 C
What I calculated was a ratio, so you can use the ratio to convert your units for each of the following to A.
To determine the boiling point of water and the temperature of absolute zero on the new temperature scale, we need to establish a linear relationship between the original Celsius scale and the new "A" scale.
We can use the formula for a straight line:
y = mx + b
where:
y = value on the new scale (in this case, "A")
x = value on the original Celsius scale
m = slope of the line
b = y-intercept
First, let's find the slope (m) of the line. We know two points on the line: (-77.75 C, 0 A) and (-33.35 C, 200 A).
m = (change in y) / (change in x)
m = (200 A - 0 A) / (-33.35 C - (-77.75 C))
m = 200 A / 44.4 C
m = 4.5 A/C
Now that we have the slope, we can find the y-intercept (b) by substituting one of the points into the equation:
0 = 4.5 A/C * (-77.75 C) + b
b = 4.5 A/C * 77.75 C
b = 348.375 A
So, the equation for converting Celsius to the new "A" scale is:
A = 4.5 C + 348.375
To find the boiling point of water on the new scale, we substitute the Celsius value of the boiling point of water (100 C) into the equation:
A = 4.5 * 100 + 348.375
A = 800 + 348.375
A = 1148.375
Therefore, the boiling point of water on the "A" scale is approximately 1148.375 A.
To find the temperature of absolute zero on the new scale, we substitute the Celsius value of absolute zero (-273.15 C) into the equation:
A = 4.5 * -273.15 + 348.375
A = -1229.175 + 348.375
A = -880.8
Therefore, the temperature of absolute zero on the "A" scale is approximately -880.8 A.
Take the difference between the C's and A's and make a conversion factor.
44.4 C=200A
bp of water in C*(200A/44.4C)= Bp of water in A
Absolute zero in C*(200A/44.4C)=Absolute zero in A