posted by Wes .
Wes and Lindsay stand on the roof of a building. Wes leans over the edge and drops an apple. Lindsay waits, 1.25s afrer Wes releases his fruit and throws an orange straight down at 28 m/s. Both pieces of fruit hit the ground simultaneously. Calculate the common height from which the fruit were released. Ignore the effects of air resistence.
This is a duplicate post. Please don't clutter the website with identical posts
I would just do this by looking at Lindsay's orange, and use conservation of kinetic energy to solve this problem. KE=PE=1/2(mv^2)=mgh and solve for h.
The masses are the same so they cancel out.
That method will give the wrong answer unless you use the kinetic energy change when it hits the ground.
I saw that after I did, I should have had him tackle it with the kinematic equations, but I believe you corrected this in a later post. Consequently, I didn't bother to post again saying ignore the setup.
Holy shzniit, this is so cool thank you.