Physics

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Wes and Lindsay stand on the roof of a building. Wes leans over the edge and drops an apple. Lindsay waits, 1.25s afrer Wes releases his fruit and throws an orange straight down at 28 m/s. Both pieces of fruit hit the ground simultaneously. Calculate the common height from which the fruit were released. Ignore the effects of air resistence.

  • Physics -

    This is a duplicate post. Please don't clutter the website with identical posts

  • Physics -

    I would just do this by looking at Lindsay's orange, and use conservation of kinetic energy to solve this problem. KE=PE=1/2(mv^2)=mgh and solve for h.

    g=9.8m/s^2

    1/2(mv^2)=mgh

    1/2(v^2)=gh

    The masses are the same so they cancel out.

    (1/2(28m/s)^2/9.8m/s^2)=h

  • Physics -

    That method will give the wrong answer unless you use the kinetic energy change when it hits the ground.

  • Physics -

    I saw that after I did, I should have had him tackle it with the kinematic equations, but I believe you corrected this in a later post. Consequently, I didn't bother to post again saying ignore the setup.

  • Physics -

    Holy shzniit, this is so cool thank you.

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