calculus

posted by .

Using an upper-case "C" for any arbitrary constants, find the general indefinite integral

∫ (-2-t)(-9-t^2) dt


Now I multiplied both parentheses to get:

∫ (18 + 2t^2 + 9t + t^3) dt

now I integrated and got:

18t + 2t^3/3 + 9t^2/2 + t^4/4 + C

but I'm told this answer is incorrect.
What am I doing wrong?

Thank you

  • calculus -

    I have
    (t^2 + 9)(t+2)
    is
    t^3 + 2 t^2 + 9 t + 18

    t^4/4 + (2/3) t^3 + (9/2) t^2 + 18 t + C

    I agree with you.

  • calculus -

    okay so there must be a mistake with the system, thanks for clearing that up Damon.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Calculus

    Suppose that ∫∫_D f(x,y)dA=3 where D is the disk x^2+y^2<=16. Now suppose E is the disk x^2+y^2<=144 and g(x)=3f(x/3,y/3), what is the value of the integral of ∫∫_E g(x,y)dA?
  2. Calculus

    Find the integral by substitution ∫ [(16 x3)/(x4 + 5)] dx ∫[ 4 x/(√{x2 + 3})] dx ∫ 8 x2 e4 x3 +7 dx PLEASE help with all three. i'd really appreciate it
  3. calculus

    Find the general indefinite integral ∫cosxsin^4xdx
  4. Calculus. I need help!

    Evaluate the indefinite integral (a.)∫√(cotx)csc^2xdx (b.)∫sec^3xtanxdx
  5. Calculus 2 correction

    I just wanted to see if my answer if correct the integral is: ∫(7x^3 + 2x - 3) / (x^2 + 2) when I do a polynomial division I get: ∫ 7x ((-12x - 3)/(x^2 + 2)) dx so then I use u = x^2 + 2 du = 2x dx 1/2 du = x dx = ∫7x …
  6. Calculus

    Find the general indefinite integral ∫ v(v3+5)2dv
  7. Calculus

    Alright, I want to see if I understand the language of these two problems and their solutions. It asks: If F(x) = [given integrand], find the derivative F'(x). So is F(x) just our function, and F'(x) our antiderivative?
  8. Applied Calc

    Find the indefinite integral of x^4/1-x^5dx. so far, I have these steps: ∫ f'(x)dx = ∫ x^4/1-x^5dx Let u=1-x^5 du= -5x^4 ∫ u^-1*-1/5du (but I'm not sure if you can technically do -1/5du?
  9. Calculus

    Integrate 1/sinx dx using the identity sinx=2(sin(x/2)cos(x/2)). I rewrote the integral to 1/2 ∫ 1/(sin(x/2)cos(x/2))dx, but I don't know how to continue. Thanks for the help. Calculus - Steve, Tuesday, January 12, 2016 at 12:45am …
  10. Calculus II

    So I'm trying to integrate a function using partial fractions. Here is the integral of interest: ∫(3x^2+5x+3)/[(x+2)(x^2+1)]dx. Since the numerator's degree of the polynomial is lesser than that of the denominator's degree, it …

More Similar Questions