how many ions of potasium are there in 4.2vgrams of K3PO4 (molar mass=212.264g/mol
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To determine the number of ions of potassium (K+) in 4.2 grams of K3PO4, we need to use the molar mass and the chemical formula of K3PO4.
1. First, calculate the number of moles of K3PO4 using the given mass and molar mass:
- Mass of K3PO4 = 4.2 grams
- Molar mass of K3PO4 = 212.264 g/mol
- Number of moles = mass / molar mass = 4.2 g / 212.264 g/mol
2. Next, use the balanced chemical formula to determine the moles of K+ ions:
- The chemical formula of K3PO4 states that there are 3 K+ ions per one K3PO4 molecule.
3. Multiply the number of moles of K3PO4 by the ratio of K+ ions to K3PO4 molecules:
- Moles of K+ ions = Moles of K3PO4 * (3 K+ ions / 1 K3PO4 molecule)
Finally, we can calculate the number of ions by multiplying the calculated moles of K+ ions by Avogadro's number (6.022 x 10^23 ions per mole).
Note: Avogadro's number represents the number of particles in one mole of a substance (6.022 x 10^23 particles/mol).
Let's calculate the number of ions of potassium (K+) in 4.2 grams of K3PO4:
1. Number of moles of K3PO4:
Moles of K3PO4 = 4.2 g / 212.264 g/mol
2. Moles of K+ ions:
Moles of K+ ions = Moles of K3PO4 * (3 K+ ions / 1 K3PO4 molecule)
3. Number of K+ ions:
Number of K+ ions = Moles of K+ ions * Avogadro's number
Perform these calculations to find the answer.