the number N of state and federal inmates in millions during year x, where x greater than or equal to 2002 can be approximated by the following formula.

N=0.05x-98.45
Determine the tear in which there were 1.7 million

you just plug in 1.7 for N and isolate the x to get the year

1.7mil= 0.05x - 98.45 its simple algebraic manipulation. you move 98.45 to other side by adding it to both side leavign you with

1.7 mil + 98.45= 0.05x and then divide both side by 0.05 to get x by itself imma assume 98.45 is millions or else this formula makes no sense to me

To determine the year in which there were 1.7 million state and federal inmates, you need to solve the equation N = 1.7, where N represents the number of inmates in millions and x represents the year.

The given formula is N = 0.05x - 98.45.

So, substitute N = 1.7 into the equation:
1.7 = 0.05x - 98.45

To solve for x, we can isolate the variable x by moving the constant term (-98.45) to the other side of the equation by adding 98.45 to both sides:

1.7 + 98.45 = 0.05x

Simplifying further:

100.15 = 0.05x

Now, divide both sides by 0.05 to solve for x:

x = 100.15 / 0.05

x = 2003

Therefore, in the year 2003, there were approximately 1.7 million state and federal inmates.