algebra

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PLEASE help with the below.

Solve the system of equations by first expressing it in matrix form as and then evaluating.


a). 3x-2y=5
4x-y =-10


b). 3x -2y =-2
4x -y = 3

  • algebra -

    uggghhh, matrices for such simple systems ???

    anyway ....

    1st one:

    3 -2 5
    4 -1 -10

    1 1 -15 ---> #2 - #1
    3 -2 5 ----> #1

    1 1 -15 ---> #1
    0 5 -50 ---> 3x#1 - #2

    1 1 -15 ---->#1
    0 1 -10 ---> #2 รท 5

    1 0 -5 ---#1 - #2
    0 1 -10 ---> #2

    so x = -5 and y = -10
    ---------------------------

    same thing using substitution

    form #2, y = 4x+10
    sub into #1
    3x - 2(4x+10) = 5
    3x - 8x - 20 = 5
    -5x = 25
    x = -5 , then y = -20+10 = -10

    You try the second one, remember in the matrix method there is no one correct way,
    what I did above just seemed like a way to me, you might have taken a different path.

  • algebra -

    Thank you.

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