You spin a spinner that is divided into 6 equals parts once and roll the number cube once. Find the probability that the spinner stops on the same number that you roll the number cube?
Wherever the spinner stops, the cube has to match that
so prob = (1)(1/6) = 1/6
or, the long way:
it could be 11 22 33 44 55 66
prob = (1/6)(1/6) + (1/6)(1/6) + ... (1/6)(1/6)
= 1/36 + 1/36+ .. + 1/36 , for 6 terms
= 6(1/36) = 1/6
To find the probability that the spinner stops on the same number as the number rolled on the number cube, we need to determine the number of favorable outcomes and the total number of possible outcomes.
Step 1: Determine the number of favorable outcomes.
Since the spinner has six equal parts, there are six possible outcomes when spinning it. Similarly, when rolling a number cube, there are six possible outcomes as well. Out of these six outcomes, only one outcome will result in the same number appearing on both the spinner and number cube. Therefore, the number of favorable outcomes is 1.
Step 2: Determine the total number of possible outcomes.
Since the spinner has six equal parts, there are six possible outcomes when spinning it. Similarly, when rolling a number cube, there are six possible outcomes as well. To find the total number of possible outcomes, we multiply the number of outcomes for both the spinner and the number cube. So, the total number of possible outcomes is 6 x 6 = 36.
Step 3: Calculate the probability.
The probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. In this case, the probability is 1 (the number of favorable outcomes) divided by 36 (the total number of possible outcomes). Therefore, the probability is 1/36.
So, the probability that the spinner stops on the same number as the number rolled on the number cube is 1/36.