What is the acceleration of a car that moves from rest to 15.0m/s in 10.0s ?
a=v-u/t where a, is the acceleration,v the final velocity,u the initial velocity and t the time.=a=x ,v=15ms`,u=0 and t=10 therefore from a=u-v/t you have a=15-0/10=1.5ms`2
Well, it seems like the car is in a hurry! Let's calculate the acceleration here.
To find acceleration, we can use the formula:
acceleration = change in velocity / time taken
The car moves from rest (0 m/s) to 15.0 m/s in 10.0 seconds, so the change in velocity is:
15.0 m/s - 0 m/s = 15.0 m/s
Now we can plug in the values into the formula:
acceleration = 15.0 m/s / 10.0 s = 1.5 m/s²
So, the acceleration of the car is 1.5 m/s². It's a speed racer!
To find the acceleration of the car, we can use the formula:
Acceleration = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 0 (since the car starts from rest)
Final velocity (v) = 15.0 m/s
Time (t) = 10.0 s
Plugging these values into the formula, we get:
Acceleration = (15.0 m/s - 0) / 10.0 s
Simplifying, we have:
Acceleration = 15.0 m/s / 10.0 s
Now, dividing the numerator by the denominator, we get:
Acceleration = 1.5 m/s²
Therefore, the acceleration of the car is 1.5 m/s².
To find the acceleration of the car, we can use the equation:
acceleration (a) = change in velocity (Δv) / time taken (Δt)
First, we need to find the change in velocity (Δv). The car starts from rest, so its initial velocity (u) is 0 m/s. The final velocity (v) is given as 15.0 m/s.
Δv = v - u
Δv = 15.0 m/s - 0 m/s
Δv = 15.0 m/s
Next, we need to find the time taken (Δt). The time taken for the car to reach a velocity of 15.0 m/s is given as 10.0 s.
Δt = 10.0 s
Now, we can substitute the values into the acceleration formula:
acceleration (a) = Δv / Δt
a = 15.0 m/s / 10.0 s
a = 1.5 m/s²
Therefore, the acceleration of the car is 1.5 m/s².