Math
posted by Barry .
A pot contains 6 liters of brine at a concentration of 120g/l. How many liters of the water should be boiled off so that concentration of the brine is 200g/l.

divide 200 by 120 to get your answer

let the amount boiled off be x L
amount of brine = 6 (120 g/L) = 720 g
that must stay constant
(6x)(200 g/L) = 720 g
1200  200x = 720
200x = 480
x = 2.4
2.4 L must be boiled off
check:
liquid left = 62.4 = 3.6 L
but there must still be 720 g in there
concentration = 720/3.6 = 200 g/L
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