A gas has a volume of 590mL at a temperature of -55.0C What volume will the gas occupy at 30.0C
Can someone help me?
Here is the answer you guys ^v^
V1/T1 = V2/T2
V1 = 590 mL
T1 = -55 + 273 = 218 K
T2 = 30 + 273 = 303 K
590/218 = V2/303
V2 = 303*590 / 218
V2 = 820.05 mL
I gave you the equation. All you must do is substitute the numbers into the equation.
V1 = 590 mL
T1 = -55C = 273+(-55) = ? Kelvin
V2 = ? solve for this.
T2 = 30 C = 273 + 30 = ? Kelvin
(V1/T1) = (V2/T2)
Remember T must be in kelvin.
dont understand
Of course! I'd be happy to help you with your question.
To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, assuming that the pressure and amount of gas are constant.
First, let's convert the given temperatures to Kelvin. To convert from Celsius to Kelvin, we add 273.15.
-55.0°C + 273.15 = 218.15 K (temperature 1)
30.0°C + 273.15 = 303.15 K (temperature 2)
Now, we can set up a proportion using the formula for Charles's Law:
V1 / T1 = V2 / T2
Where:
V1 = initial volume (590 mL)
T1 = initial temperature (218.15 K)
V2 = final volume (what we want to find)
T2 = final temperature (303.15 K)
Plugging in the given values, we get:
590 mL / 218.15 K = V2 / 303.15 K
Now we can solve for V2 by cross-multiplying and isolating V2:
(590 mL * 303.15 K) / 218.15 K = V2
V2 ≈ 817 mL
Therefore, the gas will occupy approximately 817 mL at a temperature of 30.0°C.