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CH3CH2CHO + 2Ag(NH3)2OH = CH3CH2COONH4+2Ag+H20+3NH3

yield of Ag obtained = 75%
calculate minimum mass of propanal that must have been used to form 5g of silver

  • science -

    looks like each mole of propanol produces 2 moles of Ag.

    If the reaction yields 75%, then each mole of propanol produces 1.5 moles Ag.

    So, how many moles of Ag in 5g?

    3/2 that of propanol, convert to g.

  • science -

    still confused

  • science -

    1 mole of Ag = 108 g
    So, 5g = 5/108 = 0.0463 moles Ag

    Each mole of propanol produces 1.5 moles Ag, so each mole of Ag requires 2/3 moles of propanol (sorry for the 3/2 typo above).

    2/3 * .0463 = 0.0309 moles of propanol required.

    mol wt of propanol is 58g, so you need 1.79 g

  • science -

    thankyou i appreciate it

  • science -

    thankyou i appreciate it

    could u however plz explain how u knew 1 mol of ag =108g

  • science -

    never mind i know now thankyou

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