Calculus
posted by Liz .
Use the disk method to find the volume of the solid formed by rotating the region bounded by y=2x and y=x^2 about the yaxis.

the intersect at (0,0) and (2,4)
since we are rotating around the y axis we need the radius squared, that is, we need the x^2 of each equation
from the 1st : y = 2x > x = y/2 , then x^2 = y^2/4
from the 2nd: y = x^2 > then x^2 = y , the outer
so volume
= π∫(y  y^2/4) dy from y = 0 to 4
= π[y^2/2  y^3/12] from 0 to 4
= π(16/2  64/12  0)
= 8π/3
check my arithmetic
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