The numerical value of the concentration
equilibrium constant for the gaseous reaction
2 SO2 + O2
*)
2 SO3
is 0.5 at temperature T. When a reactionmix-
ture is brought to equilibrium, [O2] is found
to be 2.0 M and [SO3] is found to be 10 M.
What is the equilibrium concentration of SO2
in this reaction mixture?
............2SO2 + O2 ==> 2SO3
E...........x.....2.0M....10M
Substitute the values into the Kc expression and solve for the one unknown.
To find the equilibrium concentration of SO2 in this reaction mixture, we can use the equation of the concentration equilibrium constant and the given values.
The concentration equilibrium constant for the given reaction is given by:
Kc = [SO3]^2 / ([SO2]^2 * [O2])
We are given that the value of Kc is 0.5 at temperature T. We are also given the equilibrium concentrations of [O2] and [SO3]:
[O2] = 2.0 M
[SO3] = 10 M
Our goal is to find the equilibrium concentration of [SO2].
Let's substitute the given values into the equation:
0.5 = (10^2) / ([SO2]^2 * 2)
Now, let's solve for [SO2].
0.5 * [SO2]^2 * 2 = 100
[SO2]^2 = 100 / (0.5 * 2)
[SO2]^2 = 100 / 1
[SO2]^2 = 100
Taking the square root of both sides:
[SO2] = sqrt(100)
[SO2] = 10 M
Therefore, the equilibrium concentration of SO2 in this reaction mixture is 10 M.