math
posted by HELP HELP HELP MNHS .
Two equal circles of radius 8cm intersect at X and Y. If the line joining the centers is 12cm long, find the length of XY.
with solution pls, tnx...

let the length of the overlap be x
then 8+8x=12
x=4
So now you can construct a rightangled triangle by joining one of the centres to X
Its hypotenue will be 8
and its base will be 8  (1/2)of4 = 6 and its height is 1/2 of XY, call it h
h^2 + 6^2 = 8^2
h^2 = 6436 = 28
h = √28 = 2√7
So XY = 4√7