200 coins are sorted and kept 3 bags. The first bag has 20 more coins than the second bag. The second bag has twice as many coins as the third bag. How many coins are there in the third bag?
x = third bag
x + 2x + 2x + 20 = 200
5x = 200 - 20
x = 180/5
x = 36
To solve this problem, let's break it down step by step.
Let's assume the number of coins in the third bag is "x". According to the information given, the second bag has twice as many coins as the third bag, so the second bag will have 2x coins.
The first bag has 20 more coins than the second bag, so it will have 2x + 20 coins.
Now, we can add up the number of coins in all three bags: x + 2x + 2x + 20 = 200 (as there are a total of 200 coins).
Combining like terms, we get 5x + 20 = 200.
Subtracting 20 from both sides, we have 5x = 180.
Finally, dividing both sides by 5, we find that x = 36.
Therefore, there are 36 coins in the third bag.