Algebra

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A rectangle was 25 cm longer than it was wide. A new rectangle was formed by decreasing the length by 6 cm and decreasing the width by 5 cm. The area of the new rectangle was 585 cm squared. Find the dimensions of the original rectangle.

  • Algebra -

    original:
    width --- x
    length -- x+25

    new one:
    width --- x-5
    length --- x+25-6 = x+19

    (x-5)(x+19) = 585
    x^2 + 14x - 95 = 585
    x^2 + 14x - 680 = 0
    (x-20)(x+34) = 0
    x = 20 or x is a negative, which would be bogus

    original
    width is 20 and length is 45

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