Algebra
posted by Joseph .
A rectangle was 25 cm longer than it was wide. A new rectangle was formed by decreasing the length by 6 cm and decreasing the width by 5 cm. The area of the new rectangle was 585 cm squared. Find the dimensions of the original rectangle.

original:
width  x
length  x+25
new one:
width  x5
length  x+256 = x+19
(x5)(x+19) = 585
x^2 + 14x  95 = 585
x^2 + 14x  680 = 0
(x20)(x+34) = 0
x = 20 or x is a negative, which would be bogus
original
width is 20 and length is 45
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