If a 1.5V battery stores 5.0kj of energy,for how many minutes could it sustain a current of 1,2A?
Energy = Power*time
Power = I^2*r = I*V = 1.5*1.2
5 * 10^3 = 1.5*1.2*time
solve for time. Your answer will be in the SI units of seconds; divide this answer by 60 sec/min to convert the answer to minutes
Well, let's calculate that in a humorous way, shall we?
If a battery could talk, it would be like, "Hey, I'm a 1.5V battery, and I've got 5.0kJ of energy!" And then the current comes along, all confident and says, "I'm 1.2A, baby!"
So, to figure out how long the battery can sustain that current, we can use the formula:
Energy (in joules) = Power (in watts) × Time (in seconds)
But we don't want to use seconds, because that's too serious. Let's convert it to minutes!
So, we know the power is the product of current and voltage. So, it's like the battery saying to the current, "Hey, I'm 1.5V, and you're 1.2A! Let's multiply and get this party started!"
1.5V × 1.2A = 1.8W
Now let's solve for time, rearranging the formula:
Time (in seconds) = Energy (in joules) / Power (in watts)
But remember, we want minutes, not seconds. So, we'll divide the time by 60.
Time (in minutes) = Time (in seconds) / 60
Now, put it all together:
Time (in minutes) = (5.0kJ / 1.8W) / 60
Calculating all of that seriously (sorry, can't be funny all the time), we find it sustains the current for approximately 4.63 minutes.
So, the battery and the current can have a good time together for about 4.63 minutes, making some electric magic happen!
To find out how long a 1.5V battery can sustain a current of 1.2A, we need to calculate the total energy provided by the battery and then divide it by the power consumption.
1. Calculate the total energy provided by the battery:
Energy (E) = Battery voltage (V) x Battery capacity (Q)
Given: Battery voltage (V) = 1.5V
Energy (E) = 1.5V x 5.0kJ = 7.5kJ
2. Convert the energy to joules:
Since 1 kJ = 1000 J, we need to convert the energy from kJ to J:
Energy (E) = 7.5kJ x 1000 = 7500J
3. Calculate the time the battery can sustain the current:
Power (P) = Voltage (V) x Current (I)
Given: Current (I) = 1.2A
Power (P) = 1.5V x 1.2A = 1.8W
To find the time, we can use the formula:
Time (t) = Energy (E) / Power (P)
Time (t) = 7500J / 1.8W
To convert watts to joules, since 1W = 1J/s, we divide by 1.8:
Time (t) = 7500J / (1.8J/s) = 4166.67 seconds
4. Convert seconds to minutes:
Since 1 minute = 60 seconds, we divide by 60 to get the time in minutes:
Time (t) = 4166.67 seconds / 60 = 69.44 minutes (rounded to 2 decimal places)
Therefore, the 1.5V battery can sustain a current of 1.2A for approximately 69.44 minutes.
To determine how long a 1.5V battery can sustain a current of 1.2A, we need to calculate the total energy stored in the battery and then divide it by the power consumed by the current.
Step 1: Calculate the energy stored in the battery.
Given that the battery stores 5.0 kJ (kilojoules) of energy, we need to convert it into joules to match the units of power we'll be using. 1 kilojoule is equal to 1000 joules. So, 5.0 kJ is equal to 5.0 x 1000 = 5000 J.
Step 2: Calculate the power consumed by the current.
The power consumed by the current can be calculated using the formula: Power (P) = Voltage (V) x Current (I).
Here, the voltage (V) is 1.5V, and the current (I) is 1.2A.
So, the power consumed by the current is P = 1.5V x 1.2A = 1.8W (watts).
Step 3: Calculate the duration the battery can sustain the current.
To find out how long the battery can sustain the current, we divide the energy stored in the battery by the power consumed by the current.
Duration (t) = Energy (E) / Power (P)
Substituting the values, we get t = 5000 J / 1.8 W = 2777.78 seconds.
Since we are asked for the duration in minutes, we need to convert seconds to minutes. There are 60 seconds in a minute.
So, 2777.78 seconds is equal to 2777.78 / 60 = 46.30 minutes.
Therefore, a 1.5V battery could sustain a current of 1.2A for approximately 46.30 minutes.