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posted by Anonymous .
find the equation of plane passing through point(0,7,7) and containing line x+1/3=y3/2=z+2/1

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Reiny
I assume you mean
(x+1)/3 = (y3)/2 = (z+2)/1 , the brackets are essential
so we know (1,3,2) is a point on the plane and we also have a direction vector of [3,2,1]
using (0,7,7) we can find a second direction vector which would be
[1,4,5]
a normal to [3,2,1] and [1,4,5] is [14, 14 , 14]
or reduced to [1,1,1]
So the equation of the plane is
x + y + z = c, but 1,3,2) lies on it
1 + 3  2 = c = 0
equation of plane:
x+y+z = 0
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