1.described the motion of mud that flies off from a rapidly spinning wheel. 2.explain why the outer rail is higher than the inner rail of curve in a railroad track.
3. a 5kg mass is moving in a circle of a radius 3m at a speed of 30 m/sec.determine the required centripetal force to keep the object moving.
4. described the similarities of the motion of the earth and the motion of the rubber stopper or rubber ball in circle.
velocity on the wheel is tangential to the wheel. Things flying off, in accordance with Newton's first law, go in a straight line
2. http://en.wikipedia.org/wiki/Rail_speed_limits_in_the_United_States
3. what is m*v^2/r
4. compare tension in the string with Gravitational attraction
please answer number 1 and 4
He did.
1. The motion of mud flying off from a rapidly spinning wheel can be explained by referencing the concept of centrifugal force. As the wheel spins, the mud particles experience a centrifugal force that causes them to move away from the center of rotation. Due to their inertia, they continue to move tangentially to the wheel, resulting in the mud being flung off in a direction perpendicular to the wheel's rotation.
2. The outer rail is higher than the inner rail in a railroad track to facilitate the smooth and safe movement of trains around a curve. This design is based on the principles of physics, specifically centripetal force. When a train goes around a curve, it experiences an outward force called centrifugal force, which tries to push it away from the curve. To counteract this force and keep the train on the track, the outer rail is elevated to create a banking angle. This banking angle allows the train to lean into the curve, effectively counterbalancing the centrifugal force and maintaining stability.
3. To determine the required centripetal force to keep the 5kg mass moving in a circle of radius 3m at a speed of 30 m/s, we can use the formula for centripetal force. Centripetal force (Fc) is given by the equation Fc = (m * v^2) / r, where m is the mass, v is the velocity, and r is the radius.
Plugging the values into the formula, we have Fc = (5 kg * (30 m/s)^2) / 3 m. Simplifying further gives us Fc = 1500 kg m/s^2, which is equal to 1500 Newtons (N). Hence, a centripetal force of 1500N is required to keep the object moving in a circle.
4. The motion of the Earth and the motion of a rubber stopper or ball in a circle share some similarities. Both involve circular motion and require a centripetal force to maintain their orbits or circular paths.
In the case of the Earth, it moves in an elliptical orbit around the Sun due to the gravitational force between the two bodies. This force acts as the centripetal force, keeping the Earth in its orbit. Similarly, a rubber stopper or ball being swung around in a circular motion experiences a centripetal force that pulls it towards the center of the circle, preventing it from flying off in a straight line.
Additionally, both the Earth and the rubber stopper or ball experience a tangential velocity, which determines the speed at which they move along their circular path. The centripetal force is responsible for continuously changing the direction of this velocity, allowing the objects to maintain their circular motion.