# chemistry

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How many ml of 0.05M kmn04 acidic are diluted to oxidize 2gm of fes04 is diluted solution

I want you step by step clearly explain

Thank you for Bob

• chemistry -

5Fe^2+ + MnO4^- ==> Mn^2+ + 5Fe^3+

mols FeSO4 = g/molar mass FeSO4
mols KMnO4 = 5 times that (look at the coefficients in the balanced equation)
M KMnO4 = mols KMnO4/L KMnO4. You know mols and M, solve for L and convert to mL.

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