posted by Em
Find the area of the region between the curves
y = sin x and y = x^2 - x, 0 ≤ x ≤ 2.
I made a rough sketch and it looks like the sine curve and the parabola intersect at x=0 and somewhere around 1.6
Not sure what methods you have at your disposal to solve x^2 - x - sin(x) = 0
but we will need that second value of x at that intersection.
Are you familiar with Newton's method?