chemistry
posted by Fai .
5ml of 8N Hn03, 4.8ml of 5N hcl and a certain volume of 17M h2s04 are mixed together and made up to 2 liter. 30ml of this acid mixture exactly neutralizes 42.9ml of na2c03, 10 h20 in 100ml of water
.Calculate the amount of sulphate ion in gm present in solution
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This can't be done with the information provided. You need a N or M of Na2CO3.10H2O.
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