Work it out. How many joules of heat is given out when pieces of iron of mass 50g and specific heat capacity =460kgk cools from 80¡èc to 20¡èc?
1380joules
heat=massiorin*specificheat*(Tf-Ti)
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The answer is correct
Answer is Correct
To calculate the amount of heat given out when the iron cools from 80°C to 20°C, you can use the formula:
Q = m * c * ΔT
Where:
Q is the amount of heat
m is the mass of the iron (in kg)
c is the specific heat capacity of iron (in J/kg°C)
ΔT is the change in temperature (in °C)
Now, let's calculate the amount of heat given out:
1. Convert the mass of iron to kilograms:
Given mass = 50g
Convert it to kg by dividing by 1000:
mass = 50g / 1000 = 0.05kg
2. The specific heat capacity of iron is given as 460 J/kg°C.
3. Calculate the change in temperature:
ΔT = final temperature - initial temperature
ΔT = 20°C - 80°C = -60°C
Since the change in temperature is negative, it means the iron is cooling.
4. Plug the values into the formula to find Q:
Q = m * c * ΔT
Q = 0.05kg * 460 J/kg°C * -60°C
5. Calculate the result:
Q = -1380 J
Therefore, the amount of heat given out when the iron cools from 80°C to 20°C is -1380 Joules. The negative sign indicates that heat is being lost or given out.