(2-√2)/(3+√2)
can you plz tell me how to solve it? plz hurry up
for god sake plz help me.
i think the answer may be this
(2-√2)/(3+√2)
(2-√2)(3-√2)/(3+√2)(3-√2)
6-2√2-3√2+2/3*3-√2*√2
8-5√2/9-2
8-5√2/7
2√2-5√2/7
=-3√2/7
(2-√2)/(3+√2)
=(2-√2)/(3+√2) * (3-√2)/(3-√2)
= (6 -2√2 - 3√2 + 2)/(9-2)
= (8 - 5√2)/7
To simplify the expression (2-√2)/(3+√2), we can use a technique called rationalizing the denominator. Here's how you can solve it step by step:
Step 1: Multiply both the numerator and denominator by the conjugate of the denominator.
The conjugate of (3+√2) is (3-√2).
((2-√2)/(3+√2)) * ((3-√2)/(3-√2))
Step 2: Simplify the expression by multiplying the numerators and the denominators:
(2(3) - 2√2 - √2(3) + √2(√2)) / (3(3) - 3√2 + 3√2 - √2(√2))
(6 - 2√2 - 3√2 + 2) / (9 - 2)
(8 - 5√2) / 7
Therefore, the simplified form of (2-√2)/(3+√2) is (8 - 5√2) / 7.