Calculus
posted by Anonymous .
the slope of the tangent line to the curve y=(3/x) at the point (6,0.5000) is?
the equation of this tangent line can be written in the form y=mx+b where m is? and where b is?

y = 3/x
y' = 3/x^2
y'(6) = 3/36 = 1/12
y1/2 = 1/12 (x6)
y = 1/12 x + 1