chem hwk help!

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Given the following reaction:
3 CaCl2 + 2 H3PO4 Ca3(PO4)2 + 6 HCl
How many grams of H3PO4 are needed to react completely with 1.837 g of CaCl2?

I don't understand at all

  • chem hwk help! -

    cmon, we just did one of these. convert grams to moles, then use the reaction to figure the relative amounts needed/produced.

    moles of input = 1.837/111 = .01655 moles CaCl2

    Each 3 CaCl2 requires 2 H3PO4

    so, 2/3 * .01655 = .011 moles H3PO4

    .011 moles H3PO4 = .011 * 98 = 1.081g

  • chem hwk help! -

    3 CaCl2 + 2 H3PO4 Ca3(PO4)2 + 6 HCl
    How many moles of HCl will be produced if 3.525 g of H3PO4 are reacted completely?

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