Chemistry 12

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The [OH-] of a solution with a PH 5.75 is

is it 5.6*10-9M?

  • Chemistry 12 -

    14-5.75= pOH

    Since pOH=-log[OH-]

    10^(-8.25)=OH-=5.62 x10^-9M

    That's what I got.

  • Chemistry 12 -

    Aww thanks soo much buddy :)

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