Calculate the average translational kinetic energy of a nitrogen molecule at 27 degree celcius
KE(tr) =3kT/2= ....
k=1.38•10⁻²³ J/K,
T=273+27=300 K.
To calculate the average translational kinetic energy of a nitrogen molecule at 27 degrees Celsius, you can use the formula for average kinetic energy:
Average Translational Kinetic Energy = (3/2) * k * T
Where:
- k is the Boltzmann constant (1.38 × 10^-23 J/K)
- T is the temperature in Kelvin
First, let's convert the temperature from Celsius to Kelvin by adding 273.15:
27 degrees Celsius + 273.15 = 300.15 K
Now, we can plug the values into the formula:
Average Translational Kinetic Energy = (3/2) * (1.38 × 10^-23 J/K) * 300.15 K
Calculating this, we get:
Average Translational Kinetic Energy ≈ 6.21 × 10^-21 Joules
Therefore, the average translational kinetic energy of a nitrogen molecule at 27 degrees Celsius is approximately 6.21 × 10^-21 Joules.