calculus
posted by Turtle .
On the graph of f(x)=7sin(7pi x), points P and Q are at consecutive lowest and highest points with P occuring before Q. Find the slope of the line which passes through P and Q

f(x)=7sin(7pi x) has a maginitude of 7
so the largest value is 7 and the minimum value is 7
The period is 2π/ (7π) = 2/7
so P and Q are 1/7 apart along the xaxis
for a period of 2/7 or 4/14
there is a zeros when x = 0
there is a max when x = 1/14
another zero when x = 2/14
there is a min when x = 3/14
and another zero at 4/14
so P is (1/14 , 7) and Q is (3/14, 7)
(check with your calculator, setting your mode to radians, and subbing in x = 1/14 and 3/14 )
slope PQ = (77)/(3/14  1/14) = 14/(1/7)
= 14(7) = 98
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