Rusty is building a doghouse for his dog, Wheezer. He is making the dimensions of the doghouse proportional to his own house, which has a length of 54 feet and a width of 36 feet. If wheezer's new home is going to have a length of 6 feet, what will be the width?
54/36 = 6/x
Cross multiply and solve for x.
54x = 216
x = 4
To find the width of Wheezer's new home, we need to use the concept of proportional relationships.
First, let's set up a proportion using the dimensions of Rusty's house and the doghouse. Since Rusty's house has a length of 54 feet and a width of 36 feet, we have:
Length of Rusty's house / Width of Rusty's house = Length of Wheezer's doghouse / Width of Wheezer's doghouse
Plugging in the values, we get:
54 feet / 36 feet = 6 feet / Width of Wheezer's doghouse
To solve for the width of Wheezer's doghouse, we can cross multiply:
54 * Width of Wheezer's doghouse = 36 * 6
Now, we can solve for the width:
Width of Wheezer's doghouse = (36 * 6) / 54
Width of Wheezer's doghouse = 216 / 54
Width of Wheezer's doghouse = 4 feet
Therefore, the width of Wheezer's new home will be 4 feet.