a 15ml sample of sulfuric acid was titrated against a solution of .0100 mol per litre of sodium hydroxide. to bring about neutralization, 25.00 ml of sodium hydroxide solution was required. calculate the concentration of the sulfuric acid
H2SO4 + 2NaOH ==> Na2SO4 + 2H2O
mols NaOH = M x L = ?
mols H2SO4 = 1/2 that (look at the coefficients)
M H2SO4 = mols H2SO4/L H2SO4
Solve for M.
To calculate the concentration of sulfuric acid, we can use the formula:
M1V1 = M2V2
Where:
M1 = the concentration of sulfuric acid
V1 = the volume of sulfuric acid (in liters)
M2 = the concentration of sodium hydroxide
V2 = the volume of sodium hydroxide (in liters)
Given:
The volume of sulfuric acid (V1) = 15 ml = 15/1000 = 0.015 L
The concentration of sodium hydroxide (M2) = 0.0100 mol/L
The volume of sodium hydroxide (V2) = 25 ml = 25/1000 = 0.025 L
Now, substitute the values into the formula and solve for M1:
M1 * 0.015 L = 0.0100 mol/L * 0.025 L
M1 = (0.0100 mol/L * 0.025 L) / 0.015 L
M1 = 0.0167 mol/L
Therefore, the concentration of sulfuric acid is 0.0167 mol/L.