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The antifreeze in a car is a 50% by weight solution of ethylene glycol, C2H6O2 in a water solvent. Calculate the boiling point and freezing point of this solution.

(For H2O, Kb=0.52 C/m Kf= 1.86 C/m

I can't even find the formula for this in my book, please help :(

  • Chemistry -

    You need to know the mass of the radiator fluid, take 50% for mass ethylene glycol and 50% H2O.
    Then mols glycol = grams/molar mass
    molality = mols glycol/kg solvent
    delta T = Kf*m
    Subtract delta T from 0 for new freezing point.

    For boiling point, mols is same, m is same, delta T = Kb*m
    Add delta T to 100 for new b.p.

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