Chemistry- Someone please help ASAP- PLEASE

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A compound contains 38.7% K, 13.9% N, and 47.4% O by mass. What is the empirical formula of the compound?

  • Chemistry- Someone please help ASAP- PLEASE -

    38.7% K =38.7g of K, 13.9% N= 13.9g of N, and 47.4% O =47.4g of O

    38.7g of K*(1 mole of K/39.1g of K)=0.990 moles of K


    13.9g of N*(1 mole of N/14.0g of N)=0.993 moles of N


    47.4g of O*(1 mole of O/16.0g of O)=2.96 moles of O


    Take the lowest number of moles and divide into each number of moles.


    K=0.990/0.990=1

    N=0.993/0.990=1

    O=2.96/0.990=3

    Empirical formula is KNO3

  • Chemistry- Someone please help ASAP- PLEASE -

    I left a note for you concerning your 1J calculation for physics.

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