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A student measures the following data regarding the heat of fusion of ice: 25.8 g ice at 0.0°C is placed into the calorimeter which contains 100.0 g water at 21.7°C. The final temperature comes to 1.5°C. The calorimeter has a heat capacity of 15.6 J/°C.
(a) Calculate the experimental ΔHfus of ice in kJ/mol.

  • Chem -

    Let x = heat fusion ice.
    (mass ice*x) + [(mass melted ice x specific heat x (Tfinal-Tinitial)] + [mass warm water x specific heat water x (Tfinal-Tinitial)] + Ccal(Tfinal-Tinitial) = 0
    Solve for x.
    Post your work if you get stuck.

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