Chem II

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A solution is prepared by dissolving 12.7 g Ca(NO3)2 in enough water to make 100.0 mL of stock solution (molar mass is 164.09-1). What is the molarity of the solution?

  • Chem II -

    {(12.7g/164.09g* mole-1)/ 0.1L}=Molarity

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