A solution is prepared by dissolving 12.7 g Ca(NO3)2 in enough water to make 100.0 mL of stock solution (molar mass is 164.09-1). What is the molarity of the solution?

{(12.7g/164.09g* mole-1)/ 0.1L}=Molarity

To find the molarity of the solution, you need to calculate the moles of Ca(NO3)2 dissolved in the given volume of solution.

Step 1: Calculate the number of moles of Ca(NO3)2:
To do this, divide the given mass of Ca(NO3)2 by its molar mass.
Molar mass of Ca(NO3)2 = 40.08 (molar mass of Ca) + (2 * 14.01) (molar mass of N) + (6 * 16.00) (molar mass of O) = 120.10 g/mol
Number of moles = Mass / Molar mass
Number of moles of Ca(NO3)2 = 12.7 g / 164.09 g/mol

Step 2: Convert the volume to liters:
Since molarity is defined as moles of the solute divided by the volume of the solution in liters, you need to convert the given volume from milliliters (mL) to liters (L).
Volume = 100.0 mL = 100.0 / 1000 = 0.100 L

Step 3: Calculate the molarity of the solution:
Molarity = moles of Ca(NO3)2 / volume of solution
Molarity = (12.7 g / 164.09 g/mol) / 0.100 L

Now, you can perform the calculation to find the molarity of the solution.