Trig

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(csc(B)+cot (B))(csc(B)-cot(B))

  • Trig -

    You have the pattern of "difference of squares"

    (csc(B)+cot (B))(csc(B)-cot(B))
    = csc^2 B - cot^2 B

    But csc^ B = 1 + cot^2B , one of the identies from
    sin^2 B + cos^2 B= 1

    so csc^2 B - cot^2 B
    = 1 + cot^2 B - cot^2 B = 1

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