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DIVIDE X^6 -7^3 -8 BY THE PRODUCT OF X+1 AND ( X^2 +4) ?????

  • maths -

    lose the CAPS LOCK, ok?

    If, as I suspect, you meant

    (x^6-7x^3-8) / (x+1)(x^2+2x+4)

    note that x^6-7x^3-8 = (x^3-8)(x^3+1)
    Now factor those two differences of cubes, ad you have

    (x-2)(x^2+2x+4)(x+1)(x^2-x+1) / (x+1)(x^2+4)
    = (x-2)(x^2-x+1)

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