Factor completely 4ab + 2a + 6b + 3
(2a + 3) (2b + 1)?
Type a^2 for a squared, etc.
As written it is not a quadratic.
To factor the expression 4ab + 2a + 6b + 3 completely, we need to look for common factors among the terms.
First, observe that the terms 4ab and 2a have a common factor of 2a. We can factor this out:
2a(2b + 1) + 3(2b + 1)
Next, we can see that the terms in parentheses, 2b + 1, are the same. Therefore, we can factor out this common binomial:
(2a + 3)(2b + 1)
So, the completely factored form of the expression is (2a + 3)(2b + 1).