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Chemistry
How do you draw Al2 + O2
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We can't draw structures on this forum. However, I don't know what Al2 + O2 is.
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Hi, the question is: in each reaction, identify what have been oxidised and reduced.
The equation is: 2Al + 3H2SO4 ---> Al2(SO4)3
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Sulfuric acid exists in solution as H⁺ and HSO₄⁻ ions, but both react with Al metal to produce
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A sample of aluminum sulfate 18-hydrate, Al2(SO4)3 · 18 H2O, containing 157.0 mg is dissolved in 1.000 L of solution. Calculate
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I am looking for answer !!
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consider the fo9rmula for Al2(SO4)3,which is used in perspirants:
a. how many moles of sulfur are present i 3.0 moles of
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No need to count atoms/molecules. In 3.0 moles, there are 9.0 moles of S In .40 moles, there are .80
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Al2(SO4)3(aq) + BaCl2(aq) BaSO4(s) + AlCl3(aq)
Consider the unbalanced equation above. A 0.680 g sample of impure Al2(SO4)3
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To find the mass percent of Al2(SO4)3 in the sample, we need to determine the amount of Al2(SO4)3
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Al2(SO4)3(aq) + BaCl2(aq) BaSO4(s) + AlCl3(aq)
Consider the unbalanced equation above. A 0.680 g sample of impure Al2(SO4)3
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To solve this problem, we need to determine the balanced equation for the reaction, and then use
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Al2(SO4)3(aq) + BaCl2(aq) BaSO4(s) + AlCl3(aq)
Consider the unbalanced equation above. A 0.680 g sample of impure Al2(SO4)3
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To find the mass percent of Al2(SO4)3 in the sample, we need to determine the mass of Al2(SO4)3
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If you were to draw diagrams (such as that shown on the right) representing aqueous solutions of each of the following ionic
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To determine the number of anions in each compound, we need to consider the chemical formulas of the
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Al2(SO3)3 + 6NaOH ----> 3Na2SO3 = 2 Al9OH)3
If 10.0g of Al2(SO3)3 is reacted with 10.0g of NaOH, determine the limiting reagent?
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I do these the long way. Moles Al2*SO4)3 = grams/molar mass = ? mols NaOH = grams/molar mass = ?
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You could draw me to fire, you could draw me to water, you could draw me to the gallows, you could draw me to any death, you
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Yes, anaphora.
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This is the equation for the formation of Al(OH)3:
6NaOH (aq) + Al2(SO4)3 (aq) �¨ 2Al(OH)3 (s) + 3Na2SO4 (aq) Would any side
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I don't think so. If too much NaOH is added, the Al(OH)3 dissolves with the formation of Al(OH)4^-
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