Formula: 2LiOH + CO2 yields Li2CO3 +H2O
Suppose a lithium hydroxide canister contains 155grams of LiOH. What mass of CO2 will the cannister be able to absorb? If it is found that after 24 hours of use the cannister has absorbed 102 grams of CO2. What percentage of its capacity was reached?
He is wrong.
To find the mass of CO2 that the canister will be able to absorb, we need to determine the molar ratio between LiOH and CO2 using the balanced chemical equation. In the equation provided, the molar ratio between LiOH and CO2 is 2:1.
First, let's calculate the molar mass of LiOH:
Li (lithium) = 6.941 g/mol
O (oxygen) = 15.999 g/mol
H (hydrogen) = 1.008 g/mol
Molar mass of LiOH = Li + O + H = 6.941 + 15.999 + 1.008 = 23.948 g/mol
Next, we will determine the number of moles of LiOH in the canister:
Moles of LiOH = Mass of LiOH / Molar mass of LiOH
Moles of LiOH = 155 g / 23.948 g/mol = 6.47 mol
Since the molar ratio of LiOH to CO2 is 2:1, we can conclude that the moles of CO2 is half the moles of LiOH.
Moles of CO2 = 6.47 mol / 2 = 3.24 mol
Now, we will calculate the mass of CO2 absorbed by the canister after 24 hours, which is given as 102 grams.
Hence, the mass of CO2 absorbed by the canister is 102 grams.
To find the percentage of its capacity reached, we compare the mass of CO2 absorbed to the mass of CO2 the canister can absorb.
Percentage of capacity reached = (Mass of CO2 absorbed / Mass of CO2 the canister can absorb) x 100%
Percentage of capacity reached = (102 g / (3.24 mol x (44.01 g/mol))) x 100%
(Note: The molar mass of CO2 is 44.01 g/mol)
Simplifying the calculation:
Percentage of capacity reached = (102 g / 141.97224 g) x 100%
Percentage of capacity reached = 71.90%
Therefore, after 24 hours of use, the canister has reached approximately 71.90% of its capacity.
a. calculate the moles of LiOH in 155grams, then half of that moles it the moles of CO2, convert that to grams.
b. convert 102 grms CO2 to moles. What percent of the moles of CO2 in a is that?
A. I calculated 1.62 moles CO2, 71.28 grams
B. 102 grams converts into 2.32 moles. Then, 1.62/2.32 *100% is 69.83%
Thanks!