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What is the osmotic pressure formed by dissolving 50.8 mg of aspirin (C9H8O4) in 0.200 L of water at 18°C?

  • Chemistry -

    mols = grams/molar mass.Solve for mols.
    M = mols/L. Solve for M.
    pi = MRT. Solve for pi = osmotic pressure.

  • Chemistry -

    I did that. doesnt it have to be liters of the total solution? so how do we factor in the asprin into the liters?

  • Chemistry -

    I beg to differ but you did not do that. If you had you would have the answer now.
    mols = 50.8E-3g/180.2 = about 0.0003 but you need to do it more accurately.
    Then 0.0003 mols/0.200L = about 0.0014
    Then pi = MRT

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