Physics
posted by Student .
A ball thrown horizontally at 22.76 m/s travels a horizontal distance of 46.81 m before hitting the ground. From what height was the ball thrown?

The time that it takes the ball to travel in the xdirection is the same amount of time that the ball takes to travel in the ydirection. Since you know the velocity of the ball and the distance, use D=V*T and solve for time (T). Once you solve for t, use t and plug it into one of the kinematic equations D=ViT+1/2(aT^2). Since in the Ydirection the initial velocity is 0 and acceleration is equal to gravity (9.8m/s^2), the equation should be give you D=1/2(9.8m/s^2)(T)^2. Solving for D gives you the height.