A football punter accelerates a football from rest to a speed of 9.1 m/s
during the time in which his toe is in contact with the ball (about 0.247 s). If the football
has a mass of 484 g, what average force does the punter exert on the ball?
impulse momentum = Ft=M*Velocity. (0.484Kg)(9.1m/s)/0.247s should give you the Force (F).
To find the average force exerted by the punter on the ball, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
In this case, the mass of the football is given as 484 g, which we need to convert to kilograms (kg) since the SI unit for mass is kg.
1 kg = 1000 g
Therefore, the mass of the football is 484 g / 1000 = 0.484 kg.
Next, we need to calculate the acceleration experienced by the football. Since the ball starts from rest and reaches a final velocity of 9.1 m/s over a time of 0.247 s, we can use the following equation:
acceleration (a) = change in velocity (Δv) / time (t)
Substituting the given values:
a = (9.1 m/s - 0 m/s) / 0.247 s
Now, we can calculate the acceleration.
a = 9.1 m/s / 0.247 s
Finally, we can use Newton's second law to find the average force exerted by the punter on the ball.
F = m * a
Substituting the values of mass (m) and acceleration (a):
F = 0.484 kg * (9.1 m/s / 0.247 s)
Calculating the average force, we get:
F ≈ 17.8 Newtons.
Therefore, the punter exerts an average force of 17.8 Newtons on the ball.