If a 930cm3 piston compresses the air in the cylinder to 1/8 its total volume, what is the pressure after the gas is compressed?
Not sure, but if since pressure in volume are inversely related you should see an increase in the pressure. so if volume decreased by 7/8, the pressure should increase by 7/8.
You don't list a pressure initially; the final pressure will be eight times (8x) the initial pressure.
Just a question, how do you get 8x the initial pressure when it decreased by 7/8?
p1 = some convenient number, say 2 atm.
v1 = 930 cc
p2 = ?
v2 = 930*1/8 = 116.25 cc.
p1v1 = p2v2
2*930 = p2*116.25
p2 = 2*930/116.25 = 16
16 is 8*2; p increased by a factor of 8.
If the volume is reduced to 1/2 its original volume the pressure must have been doubled.
If the volume is reduced to 1/3 its original volume the pressure must have been tripled.
If the volume is reduced to 1/10 its original volume the pressure must have been increased by 10 times (a factor of 10).
If the volume is decreased to 1/8 its original volume the pressure must have been increased by a factor of 8.
Got it. Should have just done the math.
To find the pressure after the gas is compressed, we can use Boyle's Law. Boyle's Law states that the pressure and volume of a gas are inversely proportional when temperature is constant.
The formula for Boyle's Law is:
P₁V₁ = P₂V₂
Where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.
In this case, we are given that the initial volume is 930 cm³ and the gas is compressed to 1/8 of its total volume. Therefore, the final volume (V₂) will be 930 cm³ / 8 = 116.25 cm³.
We can plug in the values into the equation:
P₁ * 930 cm³ = P₂ * 116.25 cm³
Now, we need to find the initial pressure (P₁) to calculate the final pressure (P₂). Unfortunately, the problem does not provide the initial pressure, so we are unable to determine the exact value of the final pressure.