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A 45kg sample of water absorbs 364kJ of heat. If the water was initially at 28.2 Celcius, what is its final temperature? How do I figure this out....HELP!

  • Chemistry -

    Note the correct spelling of celsius.
    364,000 = mass H2O x specific heat H2O x (Tfinal-Tinitial). Substitute and solve for Tf.

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