College Algebra
posted by Krissy .
The expression x^27 is not factorable using integer values. But the expression can be written in the form X^2(Square root7)^2 enabling us to factor it as a “binomial” and its conjugate: (x+square root 7)(xsquare root 7) Use this idea to factor the following expressions.
1. X^25

x^2  5 = (x+√5)(x√5)
check by expanding it