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A football punter accelerates a football from rest to a speed of 9.1 m/s
during the time in which his toe is in contact with the ball (about 0.247 s). If the football
has a mass of 484 g, what average force does the punter exert on the ball?

  • Physics -

    Impulse momentum equation. From Newtons second law, F=MA. Since acceleration (A) is Change in velocity/time, the equation turns into F=M[(Vf-Vi)]/t. Multiplying both sides of the equation by t gives you Ft=M(Vf-Vi). Since initial velocity is 0, the equation turns into Ft=MVf. Rearranging the equation, to solve for F turns the equation into F=MVf/t, plug in your values for t, Vf, and M, resulting in a rearranged formula looking like F= [(0.484Kg)(9.1m/s)]/(0.247s). Solve for F. Note that I converted g to Kg first before solving.

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